3.71 \(\int \frac {1}{x^{5/2} (a+b \text {sech}(c+d \sqrt {x}))^2} \, dx\)

Optimal. Leaf size=25 \[ \text {Int}\left (\frac {1}{x^{5/2} \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2},x\right ) \]

[Out]

Unintegrable(1/x^(5/2)/(a+b*sech(c+d*x^(1/2)))^2,x)

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Rubi [A]  time = 0.03, antiderivative size = 0, normalized size of antiderivative = 0.00, number of steps used = 0, number of rules used = 0, integrand size = 0, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.000, Rules used = {} \[ \int \frac {1}{x^{5/2} \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Int[1/(x^(5/2)*(a + b*Sech[c + d*Sqrt[x]])^2),x]

[Out]

Defer[Int][1/(x^(5/2)*(a + b*Sech[c + d*Sqrt[x]])^2), x]

Rubi steps

\begin {align*} \int \frac {1}{x^{5/2} \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2} \, dx &=\int \frac {1}{x^{5/2} \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2} \, dx\\ \end {align*}

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Mathematica [A]  time = 67.06, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{5/2} \left (a+b \text {sech}\left (c+d \sqrt {x}\right )\right )^2} \, dx \]

Verification is Not applicable to the result.

[In]

Integrate[1/(x^(5/2)*(a + b*Sech[c + d*Sqrt[x]])^2),x]

[Out]

Integrate[1/(x^(5/2)*(a + b*Sech[c + d*Sqrt[x]])^2), x]

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fricas [A]  time = 0.43, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\sqrt {x}}{b^{2} x^{3} \operatorname {sech}\left (d \sqrt {x} + c\right )^{2} + 2 \, a b x^{3} \operatorname {sech}\left (d \sqrt {x} + c\right ) + a^{2} x^{3}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(5/2)/(a+b*sech(c+d*x^(1/2)))^2,x, algorithm="fricas")

[Out]

integral(sqrt(x)/(b^2*x^3*sech(d*sqrt(x) + c)^2 + 2*a*b*x^3*sech(d*sqrt(x) + c) + a^2*x^3), x)

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giac [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \mathit {sage}_{0} x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(5/2)/(a+b*sech(c+d*x^(1/2)))^2,x, algorithm="giac")

[Out]

sage0*x

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maple [A]  time = 0.64, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{\frac {5}{2}} \left (a +b \,\mathrm {sech}\left (c +d \sqrt {x}\right )\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/x^(5/2)/(a+b*sech(c+d*x^(1/2)))^2,x)

[Out]

int(1/x^(5/2)/(a+b*sech(c+d*x^(1/2)))^2,x)

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maxima [A]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {2 \, {\left (6 \, a b^{2} + {\left (a^{3} d e^{\left (2 \, c\right )} - a b^{2} d e^{\left (2 \, c\right )}\right )} \sqrt {x} e^{\left (2 \, d \sqrt {x}\right )} + 2 \, {\left (3 \, b^{3} e^{c} + {\left (a^{2} b d e^{c} - b^{3} d e^{c}\right )} \sqrt {x}\right )} e^{\left (d \sqrt {x}\right )} + {\left (a^{3} d - a b^{2} d\right )} \sqrt {x}\right )}}{3 \, {\left ({\left (a^{5} d e^{\left (2 \, c\right )} - a^{3} b^{2} d e^{\left (2 \, c\right )}\right )} x^{2} e^{\left (2 \, d \sqrt {x}\right )} + 2 \, {\left (a^{4} b d e^{c} - a^{2} b^{3} d e^{c}\right )} x^{2} e^{\left (d \sqrt {x}\right )} + {\left (a^{5} d - a^{3} b^{2} d\right )} x^{2}\right )}} - \int \frac {2 \, {\left (4 \, a b^{2} \sqrt {x} + {\left (4 \, b^{3} \sqrt {x} e^{c} + {\left (2 \, a^{2} b d e^{c} - b^{3} d e^{c}\right )} x\right )} e^{\left (d \sqrt {x}\right )}\right )}}{{\left (a^{5} d e^{\left (2 \, c\right )} - a^{3} b^{2} d e^{\left (2 \, c\right )}\right )} x^{\frac {7}{2}} e^{\left (2 \, d \sqrt {x}\right )} + 2 \, {\left (a^{4} b d e^{c} - a^{2} b^{3} d e^{c}\right )} x^{\frac {7}{2}} e^{\left (d \sqrt {x}\right )} + {\left (a^{5} d - a^{3} b^{2} d\right )} x^{\frac {7}{2}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x^(5/2)/(a+b*sech(c+d*x^(1/2)))^2,x, algorithm="maxima")

[Out]

-2/3*(6*a*b^2 + (a^3*d*e^(2*c) - a*b^2*d*e^(2*c))*sqrt(x)*e^(2*d*sqrt(x)) + 2*(3*b^3*e^c + (a^2*b*d*e^c - b^3*
d*e^c)*sqrt(x))*e^(d*sqrt(x)) + (a^3*d - a*b^2*d)*sqrt(x))/((a^5*d*e^(2*c) - a^3*b^2*d*e^(2*c))*x^2*e^(2*d*sqr
t(x)) + 2*(a^4*b*d*e^c - a^2*b^3*d*e^c)*x^2*e^(d*sqrt(x)) + (a^5*d - a^3*b^2*d)*x^2) - integrate(2*(4*a*b^2*sq
rt(x) + (4*b^3*sqrt(x)*e^c + (2*a^2*b*d*e^c - b^3*d*e^c)*x)*e^(d*sqrt(x)))/((a^5*d*e^(2*c) - a^3*b^2*d*e^(2*c)
)*x^(7/2)*e^(2*d*sqrt(x)) + 2*(a^4*b*d*e^c - a^2*b^3*d*e^c)*x^(7/2)*e^(d*sqrt(x)) + (a^5*d - a^3*b^2*d)*x^(7/2
)), x)

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mupad [A]  time = 0.00, size = -1, normalized size = -0.04 \[ \int \frac {1}{x^{5/2}\,{\left (a+\frac {b}{\mathrm {cosh}\left (c+d\,\sqrt {x}\right )}\right )}^2} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(x^(5/2)*(a + b/cosh(c + d*x^(1/2)))^2),x)

[Out]

int(1/(x^(5/2)*(a + b/cosh(c + d*x^(1/2)))^2), x)

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sympy [A]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {1}{x^{\frac {5}{2}} \left (a + b \operatorname {sech}{\left (c + d \sqrt {x} \right )}\right )^{2}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/x**(5/2)/(a+b*sech(c+d*x**(1/2)))**2,x)

[Out]

Integral(1/(x**(5/2)*(a + b*sech(c + d*sqrt(x)))**2), x)

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